Talk:Banach–Alaoglu theorem

This showed up in Wikipedia:Deletion_log_archive/June_2003 where it seems someone had unsuccessfully started to put in a proof. I hope this is more acceptable, even if it is a bare sketch. -- AndrewKepert 08:36, 5 Apr 2004 (UTC)

Why is it so complicated!!!!!!!!! I'm copying the first lines (that are clear) from the intro and put it as a section — Preceding unsigned comment added by Noix07 (talk • contribs) 15:05, 12 December 2013 (UTC)[reply]

Sequencially compact

All the applications of the Banach-Alaoglu theorem I know make use of sequencially compactness. Is this a consequence of compactness in this case (or for certain spaces)?--Trigamma 18:41, 17 January 2007 (UTC)[reply]

Consequences Section

It says there

 The corresponding result for p=1 is not true, as L1(μ) is not reflexive. (*)

however, this does not follow from

 If X is a reflexive Banach space, then every bounded sequence in X has a weakly convergent subsequence.

(the two are actually equivalent, so (*) holds true, but that's not clear from the article). —Preceding unsigned comment added by 84.191.204.239 (talk) 15:45, 17 March 2009 (UTC)[reply]